## How many ways are there to elect a president vice president secretary and treasurer from a club of 32 members?

**32** x 31 x 30 x 29 and that equals 863,040. 863,040 possible **ways** of **electing** four officers from a **club of 32 members**.

## How many ways can a president vice president and treasurer be elected from a group of 40 students?

1 Answer. Patrick H. There are 5040 **different ways** a **president**, **vice president**, secretary, and **treasurer can** be **selected**.

## How many ways can a president vice president secretary and treasurer be chosen from a club with 9 members assume that no member can hold more than one office?

The answer is 504.

## How many ways can a president vice president and secretary be chosen from a club with 12 members?

in how many ways can a president, vice president, and a secretary be chosen? is it 12X11X10. Permutation of n things taken r at a time: nPr=n!/(n-r)! 12P3=12*11*10*9!/9!= 12*11*10=**1320 ways**.

## How many ways can a 30 member group elect a president and vice president?

There are **30 ways** to fill the **president** slot. Leaving 29 people to fill the **V.P.** slot and 28 people to fill the Sec/ Treas slot since you wouldn’t want one person to have two of those jobs. Therefore, the solution is or 24,360 **ways**.

## How many ways can a president vice president and secretary be chosen from a club with 7 members?

How many ways can a president, vice-president, and secretary be chosen from a committee of 7 people? 7*6*5=**210 WAYS** TO SELECT THESE 3 POSITIONS.

## How many ways can a stylist Arrange 5 of 8 vases from left to right in a store display?

How many ways can a stylist arrange 5 of 8 vases from left to right in a store display? Divide out common factors. There are **6720 ways** that the vases can be arranged.

## How do you calculate permutations?

One could say that a **permutation** is an ordered combination. The number of **permutations** of n objects taken r at a time is determined by the following **formula**: P(n,r)=n! (n−r)!

## How many ways May 5 students be seated in a row of 5 chairs for a pictorial?

As you found, there are 120 total permutations. There are 2⋅4⋅3⋅2⋅1=48 permutations where D is in either **chair** 1 or **5**.

## How many ways can a baseball manager arrange a batting order of 9 players?

(9−9)! =9! 1=9! And in the end, whichever way you write it, you get **362,880 ways** to set up the batting order.

## How many ways can a president comma vice dash president comma Secretary comma and treasurer be chosen from a committee of 9 people?

1 Expert Answer

Thus, there are **9***8 = 72 **ways** to choose a **president** and **vice president**.

## How many ways can you choose the 5 cards?

= **2598960** different ways to choose 5 cards from the available **52** cards.

## How many ways can a committee of 3 be selected from a club with 12 members?

There are 12*11*10 = **1320** different ways to choose 3 students from 12 assuming order matters. If order doesn’t matter, then there are **1320**/3! = **1320**/6 = **220 ways** to form the committee.

## How many ways May 4 cards be drawn randomly from a deck of 52 cards?

The number of **ways** to choose **4 cards** from **52** is 52C4 = (**52** x 51 x 50 x 49)/(**4** x 3 x 2) = 13 x 17 x 25 x 49 = 270,725.

## What does 10P5 mean?

In calculator P is permutation so, **10P5** = 30240. webew7 and 1 more users found this answer helpful.